※ Basic error calculation tool used gauge instructions:

  1. First of all, the first drop-down list box (top left instructions first △ Department) to select the error in the calculation of the pressure gauge measuring the upper limit (the maximum volume limit only).
  2. In the second drop-down list box (top left second △ instructions Office) to select the error in calculating the pressure gauge precision.
  3. In the third drop-down list box (below left instructions first △ Department) to select the error in the calculation of the pressure gauge dial number of the sub-lattice.
  4. The first text box (top left third △ instructions Agency) shows the pressure gauge is calculated error values (both the basic error of indication only), its unit is MPa.
  5. The second text box (below left instructions a second office △) is shown in the dial gauge to calculate the minimum value of sub-lattice, the unit is MPa.
  6. The final text box shows the calculated error value is equivalent to gauge the size of the smallest sub-grid.
△Pressure gauge is the most commonly used industrial process instruments, pressure gauge to allow calculation of the basic error of the natural common. Manometer variety, the basic error of calculation of pressure gauge is relatively complicated. This tool can not only gauge the basic error of calculation, but also calculate the various gauge the value of the smallest sub-lattice. the same time, provides a popular and intuitive basic error gauge the relative size of the smallest sub-grid!
The first step: the upper limit of selection pressure measurement: 
 MPa
Step Two: Select Pressure Gauge Accuracy class: 
 %
Come: the basic error limit gauge±  
 MPa
Step Three: Select the dial gauge the total number of sub-grid: 
Drawn: the smallest sub-dial cell value: 
 MPa；
Basic error limit is equivalent to±    
 A minimum sub-grid
   
 
※ The error calculation tool applies pressure gauge：
▲ For 4.0; 2.5; 1.6; 1.0; 0.4; 0.25; 0.16; 0.1 gauge.
▲ Pressure vacuum gauge dial joint schedule of the total number of sub-grid should be negative pressure and positive pressure compartments Conjecture.